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x(x-1)-2x=-(x+50+)
We move all terms to the left:
x(x-1)-2x-(-(x+50+))=0
We add all the numbers together, and all the variables
x(x-1)-2x-(-(+x))=0
We add all the numbers together, and all the variables
-2x+x(x-1)-(-(+x))=0
We multiply parentheses
x^2-2x-1x-(-(+x))=0
We calculate terms in parentheses: -(-(+x)), so:We add all the numbers together, and all the variables
-(+x)
We get rid of parentheses
-x
Back to the equation:
-(-x)
x^2-2x-1x-(-1x)=0
We add all the numbers together, and all the variables
x^2-3x-(-1x)=0
We get rid of parentheses
x^2-3x+1x=0
We add all the numbers together, and all the variables
x^2-2x=0
a = 1; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·1·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*1}=\frac{4}{2} =2 $
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