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x(x+6)=8(x+3)
We move all terms to the left:
x(x+6)-(8(x+3))=0
We multiply parentheses
x^2+6x-(8(x+3))=0
We calculate terms in parentheses: -(8(x+3)), so:We get rid of parentheses
8(x+3)
We multiply parentheses
8x+24
Back to the equation:
-(8x+24)
x^2+6x-8x-24=0
We add all the numbers together, and all the variables
x^2-2x-24=0
a = 1; b = -2; c = -24;
Δ = b2-4ac
Δ = -22-4·1·(-24)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*1}=\frac{-8}{2} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*1}=\frac{12}{2} =6 $
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