x(x+5)=x(x+5)-3+1

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Solution for x(x+5)=x(x+5)-3+1 equation:



x(x+5)=x(x+5)-3+1
We move all terms to the left:
x(x+5)-(x(x+5)-3+1)=0
We multiply parentheses
x^2+5x-(x(x+5)-3+1)=0
We calculate terms in parentheses: -(x(x+5)-3+1), so:
x(x+5)-3+1
We add all the numbers together, and all the variables
x(x+5)-2
We multiply parentheses
x^2+5x-2
Back to the equation:
-(x^2+5x-2)
We get rid of parentheses
x^2-x^2+5x-5x+2=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation

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