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x(x+49)=2
We move all terms to the left:
x(x+49)-(2)=0
We multiply parentheses
x^2+49x-2=0
a = 1; b = 49; c = -2;
Δ = b2-4ac
Δ = 492-4·1·(-2)
Δ = 2409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{2409}}{2*1}=\frac{-49-\sqrt{2409}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{2409}}{2*1}=\frac{-49+\sqrt{2409}}{2} $
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