x(x+4)+x(x+2)=2x2+12

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Solution for x(x+4)+x(x+2)=2x2+12 equation: 



x(x+4)+x(x+2)=2x^2+12

We move all terms to the left:

x(x+4)+x(x+2)-(2x^2+12)=0

We multiply parentheses

x^2+x^2+4x+2x-(2x^2+12)=0

We get rid of parentheses

x^2+x^2-2x^2+4x+2x-12=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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