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x(x+32)=528
We move all terms to the left:
x(x+32)-(528)=0
We multiply parentheses
x^2+32x-528=0
a = 1; b = 32; c = -528;
Δ = b2-4ac
Δ = 322-4·1·(-528)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-56}{2*1}=\frac{-88}{2} =-44 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+56}{2*1}=\frac{24}{2} =12 $
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