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x(x+30)=60
We move all terms to the left:
x(x+30)-(60)=0
We multiply parentheses
x^2+30x-60=0
a = 1; b = 30; c = -60;
Δ = b2-4ac
Δ = 302-4·1·(-60)
Δ = 1140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1140}=\sqrt{4*285}=\sqrt{4}*\sqrt{285}=2\sqrt{285}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{285}}{2*1}=\frac{-30-2\sqrt{285}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{285}}{2*1}=\frac{-30+2\sqrt{285}}{2} $
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