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x(x+3)=22/9
We move all terms to the left:
x(x+3)-(22/9)=0
We add all the numbers together, and all the variables
x(x+3)-(+22/9)=0
We multiply parentheses
x^2+3x-(+22/9)=0
We get rid of parentheses
x^2+3x-22/9=0
We multiply all the terms by the denominator
x^2*9+3x*9-22=0
Wy multiply elements
9x^2+27x-22=0
a = 9; b = 27; c = -22;
Δ = b2-4ac
Δ = 272-4·9·(-22)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-39}{2*9}=\frac{-66}{18} =-3+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+39}{2*9}=\frac{12}{18} =2/3 $
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