x(x+2)=x(x-3)+5

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Solution for x(x+2)=x(x-3)+5 equation:


Simplifying
x(x + 2) = x(x + -3) + 5

Reorder the terms:
x(2 + x) = x(x + -3) + 5
(2 * x + x * x) = x(x + -3) + 5
(2x + x2) = x(x + -3) + 5

Reorder the terms:
2x + x2 = x(-3 + x) + 5
2x + x2 = (-3 * x + x * x) + 5
2x + x2 = (-3x + x2) + 5

Reorder the terms:
2x + x2 = 5 + -3x + x2

Add '-1x2' to each side of the equation.
2x + x2 + -1x2 = 5 + -3x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
2x + 0 = 5 + -3x + x2 + -1x2
2x = 5 + -3x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
2x = 5 + -3x + 0
2x = 5 + -3x

Solving
2x = 5 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.
2x + 3x = 5 + -3x + 3x

Combine like terms: 2x + 3x = 5x
5x = 5 + -3x + 3x

Combine like terms: -3x + 3x = 0
5x = 5 + 0
5x = 5

Divide each side by '5'.
x = 1

Simplifying
x = 1

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