x(x+2)+(2x+6)(x+1)+x(x)=189

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Solution for x(x+2)+(2x+6)(x+1)+x(x)=189 equation: 



x(x+2)+(2x+6)(x+1)+x(x)=189

We move all terms to the left:

x(x+2)+(2x+6)(x+1)+x(x)-(189)=0

We multiply parentheses

x^2+2x+(2x+6)(x+1)+xx-189=0

We multiply parentheses ..

x^2+(+2x^2+2x+6x+6)+2x+xx-189=0

We get rid of parentheses

x^2+2x^2+2x+6x+2x+xx+6-189=0

We add all the numbers together, and all the variables

3x^2+10x+xx-183=0

We move all terms containing x to the left, all other terms to the right

3x^2+10x+xx=183

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