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x(x+18)=x/2+39
We move all terms to the left:
x(x+18)-(x/2+39)=0
We multiply parentheses
x^2+18x-(x/2+39)=0
We get rid of parentheses
x^2+18x-x/2-39=0
We multiply all the terms by the denominator
x^2*2+18x*2-x-39*2=0
We add all the numbers together, and all the variables
x^2*2-1x+18x*2-78=0
Wy multiply elements
2x^2-1x+36x-78=0
We add all the numbers together, and all the variables
2x^2+35x-78=0
a = 2; b = 35; c = -78;
Δ = b2-4ac
Δ = 352-4·2·(-78)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-43}{2*2}=\frac{-78}{4} =-19+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+43}{2*2}=\frac{8}{4} =2 $
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