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x(x+10)=2(5x-2)
We move all terms to the left:
x(x+10)-(2(5x-2))=0
We multiply parentheses
x^2+10x-(2(5x-2))=0
We calculate terms in parentheses: -(2(5x-2)), so:We get rid of parentheses
2(5x-2)
We multiply parentheses
10x-4
Back to the equation:
-(10x-4)
x^2+10x-10x+4=0
We add all the numbers together, and all the variables
x^2+4=0
a = 1; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·1·4
Δ = -16
Delta is less than zero, so there is no solution for the equation
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