x(x+1)=2x2+5

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Solution for x(x+1)=2x2+5 equation: 



x(x+1)=2x^2+5

We move all terms to the left:

x(x+1)-(2x^2+5)=0

We multiply parentheses

x^2+x-(2x^2+5)=0

We get rid of parentheses

x^2-2x^2+x-5=0

We add all the numbers together, and all the variables

-1x^2+x-5=0

a = -1; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-1)·(-5)
Δ = -19
Delta is less than zero, so there is no solution for the equation

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