x(x+1)=-1-3x(x+1)

Solution for x(x+1)=-1-3x(x+1) equation:

x(x+1)=-1-3x(x+1)

We move all terms to the left:

x(x+1)-(-1-3x(x+1))=0

We multiply parentheses

x^2+x-(-1-3x(x+1))=0


We calculate terms in parentheses: -(-1-3x(x+1)), so:

-1-3x(x+1)

determiningTheFunctionDomain
-3x(x+1)-1

We multiply parentheses

-3x^2-3x-1

Back to the equation:

-(-3x^2-3x-1)


We get rid of parentheses

x^2+3x^2+3x+x+1=0

We add all the numbers together, and all the variables

4x^2+4x+1=0

a = 4; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·4·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-4}{8}=-1/2$