x(x)=(x+4)(x-3)

Solution for x(x)=(x+4)(x-3) equation:

x(x)=(x+4)(x-3)

We move all terms to the left:

x(x)-((x+4)(x-3))=0

We multiply parentheses ..

-((+x^2-3x+4x-12))+xx=0


We calculate terms in parentheses: -((+x^2-3x+4x-12)), so:

(+x^2-3x+4x-12)

We get rid of parentheses

x^2-3x+4x-12

We add all the numbers together, and all the variables

x^2+x-12

Back to the equation:

-(x^2+x-12)


We get rid of parentheses

-x^2-x+xx+12=0

We add all the numbers together, and all the variables

-1x^2-1x+xx+12=0

We move all terms containing x to the left, all other terms to the right

-1x^2-1x+xx=-12