x(X+5)=x2+x+32

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Solution for x(X+5)=x2+x+32 equation: 



x(x+5)=x2+x+32

We move all terms to the left:

x(x+5)-(x2+x+32)=0

We add all the numbers together, and all the variables

-(+x^2+x+32)+x(x+5)=0

We multiply parentheses

-(+x^2+x+32)+x^2+5x=0

We get rid of parentheses

-x^2+x^2-x+5x-32=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8

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