x(9+x)=162

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Solution for x(9+x)=162 equation:



x(9+x)=162
We move all terms to the left:
x(9+x)-(162)=0
We add all the numbers together, and all the variables
x(x+9)-162=0
We multiply parentheses
x^2+9x-162=0
a = 1; b = 9; c = -162;
Δ = b2-4ac
Δ = 92-4·1·(-162)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-27}{2*1}=\frac{-36}{2} =-18 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+27}{2*1}=\frac{18}{2} =9 $

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