x(7x-5)=(7x+1)(x-4)

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Solution for x(7x-5)=(7x+1)(x-4) equation: 



x(7x-5)=(7x+1)(x-4)

We move all terms to the left:

x(7x-5)-((7x+1)(x-4))=0

We multiply parentheses

7x^2-5x-((7x+1)(x-4))=0

We multiply parentheses ..

7x^2-((+7x^2-28x+x-4))-5x=0



We calculate terms in parentheses: -((+7x^2-28x+x-4)), so:

(+7x^2-28x+x-4)

We get rid of parentheses

7x^2-28x+x-4

We add all the numbers together, and all the variables

7x^2-27x-4

Back to the equation:

-(7x^2-27x-4)



We add all the numbers together, and all the variables

7x^2-5x-(7x^2-27x-4)=0

We get rid of parentheses

7x^2-7x^2-5x+27x+4=0

We add all the numbers together, and all the variables

22x+4=0

We move all terms containing x to the left, all other terms to the right

22x=-4

x=-4/22

x=-2/11

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