x(6x+1)=(2x-5)(3x+4)

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Solution for x(6x+1)=(2x-5)(3x+4) equation: 



x(6x+1)=(2x-5)(3x+4)

We move all terms to the left:

x(6x+1)-((2x-5)(3x+4))=0

We multiply parentheses

6x^2+x-((2x-5)(3x+4))=0

We multiply parentheses ..

6x^2-((+6x^2+8x-15x-20))+x=0



We calculate terms in parentheses: -((+6x^2+8x-15x-20)), so:

(+6x^2+8x-15x-20)

We get rid of parentheses

6x^2+8x-15x-20

We add all the numbers together, and all the variables

6x^2-7x-20

Back to the equation:

-(6x^2-7x-20)



We add all the numbers together, and all the variables

6x^2+x-(6x^2-7x-20)=0

We get rid of parentheses

6x^2-6x^2+x+7x+20=0

We add all the numbers together, and all the variables

8x+20=0

We move all terms containing x to the left, all other terms to the right

8x=-20

x=-20/8

x=-2+1/2

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