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x(5x-24)=36
We move all terms to the left:
x(5x-24)-(36)=0
We multiply parentheses
5x^2-24x-36=0
a = 5; b = -24; c = -36;
Δ = b2-4ac
Δ = -242-4·5·(-36)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-36}{2*5}=\frac{-12}{10} =-1+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+36}{2*5}=\frac{60}{10} =6 $
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