x(4x+8)=4(x2-1)

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Solution for x(4x+8)=4(x2-1) equation: 



x(4x+8)=4(x2-1)

We move all terms to the left:

x(4x+8)-(4(x2-1))=0

We add all the numbers together, and all the variables

-(4(+x^2-1))+x(4x+8)=0

We multiply parentheses

-(4(+x^2-1))+4x^2+8x=0



We calculate terms in parentheses: -(4(+x^2-1)), so:

4(+x^2-1)

We multiply parentheses

4x^2-4

Back to the equation:

-(4x^2-4)



We add all the numbers together, and all the variables

4x^2+8x-(4x^2-4)=0

We get rid of parentheses

4x^2-4x^2+8x+4=0

We add all the numbers together, and all the variables

8x+4=0

We move all terms containing x to the left, all other terms to the right

8x=-4

x=-4/8

x=-1/2

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