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x(4x+6x)=28
We move all terms to the left:
x(4x+6x)-(28)=0
We add all the numbers together, and all the variables
x(+10x)-28=0
We multiply parentheses
10x^2-28=0
a = 10; b = 0; c = -28;
Δ = b2-4ac
Δ = 02-4·10·(-28)
Δ = 1120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1120}=\sqrt{16*70}=\sqrt{16}*\sqrt{70}=4\sqrt{70}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{70}}{2*10}=\frac{0-4\sqrt{70}}{20} =-\frac{4\sqrt{70}}{20} =-\frac{\sqrt{70}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{70}}{2*10}=\frac{0+4\sqrt{70}}{20} =\frac{4\sqrt{70}}{20} =\frac{\sqrt{70}}{5} $
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