x(4-x)-(5-x)(x+5)=x(x+1)

Solution for x(4-x)-(5-x)(x+5)=x(x+1) equation:

x(4-x)-(5-x)(x+5)=x(x+1)

We move all terms to the left:

x(4-x)-(5-x)(x+5)-(x(x+1))=0

We add all the numbers together, and all the variables

x(-1x+4)-(-1x+5)(x+5)-(x(x+1))=0

We multiply parentheses

-1x^2+4x-(-1x+5)(x+5)-(x(x+1))=0

We multiply parentheses ..

-1x^2-(-1x^2-5x+5x+25)+4x-(x(x+1))=0


We calculate terms in parentheses: -(x(x+1)), so:

x(x+1)

We multiply parentheses

x^2+x

Back to the equation:

-(x^2+x)


We get rid of parentheses

-1x^2+1x^2-x^2+5x-5x+4x-x-25=0

We add all the numbers together, and all the variables

-1x^2+3x-25=0

a = -1; b = 3; c = -25;
Δ = b2-4ac
Δ = 32-4·(-1)·(-25)
Δ = -91
Delta is less than zero, so there is no solution for the equation