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x(3x-7)(-2+4)=0
We add all the numbers together, and all the variables
x(3x-7)2=0
We multiply parentheses
6x^2-14x=0
a = 6; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·6·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*6}=\frac{0}{12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*6}=\frac{28}{12} =2+1/3 $
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