x(3x-3)+x(2x-6)=(5x+4)(x+3)

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Solution for x(3x-3)+x(2x-6)=(5x+4)(x+3) equation:



x(3x-3)+x(2x-6)=(5x+4)(x+3)
We move all terms to the left:
x(3x-3)+x(2x-6)-((5x+4)(x+3))=0
We multiply parentheses
3x^2+2x^2-3x-6x-((5x+4)(x+3))=0
We multiply parentheses ..
3x^2+2x^2-((+5x^2+15x+4x+12))-3x-6x=0
We calculate terms in parentheses: -((+5x^2+15x+4x+12)), so:
(+5x^2+15x+4x+12)
We get rid of parentheses
5x^2+15x+4x+12
We add all the numbers together, and all the variables
5x^2+19x+12
Back to the equation:
-(5x^2+19x+12)
We add all the numbers together, and all the variables
5x^2-9x-(5x^2+19x+12)=0
We get rid of parentheses
5x^2-5x^2-9x-19x-12=0
We add all the numbers together, and all the variables
-28x-12=0
We move all terms containing x to the left, all other terms to the right
-28x=12
x=12/-28
x=-3/7

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