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x(3x+6)=3(x-10
We move all terms to the left:
x(3x+6)-(3(x-10)=0
We multiply parentheses
3x^2+6x-(3(x-10)=0
We calculate terms in parentheses: -(3(x-10), so:
3(x-10
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3(x-10
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3(x-10
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3(x-10
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3(x-10
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3(x-10
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3(x-10
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| 34=k/5-(-26) | | 3·(2x+5)+(4+4x)=7 | | 2π+69t=√33 | | 12+9x-120-9x=54 | | ⅓x+4=1 | | 3·(x-1)=x+11 | | 7x−4=−7x+52 | | $$7x−4=−7x+52 | | $$7x+3=6x+8 | | 1=g+11 | | 21=-2x+180 | | 18=3(p+15) | | -4(f-13)=-8 | | 7(x+9)=5(x-4) | | 13=6d+-11 | | 2x+22=5x-15 | | z=–9,z2= | | 2(x3)-2(x+1)=-(x+1) | | 22x-34=18x+18X | | -1.12=2w-6 | | 3x/7+6=-7 | | 9x+13=7x-9X= | | 3(u-7)=3 | | u/2+37=30 | | 3x-3=-3(7x-5)+30 | | 25x²-26x+156=0 | | 2•(x+5)=18 | | 5(z-78)=15 | | 5x-21=4x-12 | | -9(c-95)=18 | | 5*(x/x)=50 | | 5*√x=50 |