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x(3x+3)=85
We move all terms to the left:
x(3x+3)-(85)=0
We multiply parentheses
3x^2+3x-85=0
a = 3; b = 3; c = -85;
Δ = b2-4ac
Δ = 32-4·3·(-85)
Δ = 1029
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1029}=\sqrt{49*21}=\sqrt{49}*\sqrt{21}=7\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-7\sqrt{21}}{2*3}=\frac{-3-7\sqrt{21}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+7\sqrt{21}}{2*3}=\frac{-3+7\sqrt{21}}{6} $
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