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x(3x+15)=1080
We move all terms to the left:
x(3x+15)-(1080)=0
We multiply parentheses
3x^2+15x-1080=0
a = 3; b = 15; c = -1080;
Δ = b2-4ac
Δ = 152-4·3·(-1080)
Δ = 13185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13185}=\sqrt{9*1465}=\sqrt{9}*\sqrt{1465}=3\sqrt{1465}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3\sqrt{1465}}{2*3}=\frac{-15-3\sqrt{1465}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3\sqrt{1465}}{2*3}=\frac{-15+3\sqrt{1465}}{6} $
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