If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(3x+1)=240
We move all terms to the left:
x(3x+1)-(240)=0
We multiply parentheses
3x^2+x-240=0
a = 3; b = 1; c = -240;
Δ = b2-4ac
Δ = 12-4·3·(-240)
Δ = 2881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2881}}{2*3}=\frac{-1-\sqrt{2881}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2881}}{2*3}=\frac{-1+\sqrt{2881}}{6} $
| 37=-v/5 | | (3x-10)=(5x) | | 6+2p=12 | | 9^(2x+1)=30-34^4x | | 0.2=-7.4+a | | 15=v-3+13 | | 8+7(2u-2)=-4(2u-3)+8u | | 6a=78.a= | | 90.75=0.0825x+x | | 16q^2=9 | | 22.6=b-2.4 | | 20=2f=6 | | 4j-9=7 | | 2(4x+5)=10x+1-2x+9 | | x2-16+64=0 | | m/4-12=-9 | | 7x+3x-2=2(5x+2) | | 1/4k=3(-1/4k-3) | | -3+3h=-6 | | -11=18+c | | 4x+16x-6=5(4x+6) | | 1/4p=7 | | d/3+3=6 | | X*x+x=58 | | 2(k−7)=6 | | -321+w=123 | | 5(u+4)=-3(6u-9)+9u | | (x+94)=95x | | 4-j=-6 | | x-4.2=9.1 | | 2p+8=4 | | 8x-5=+2x |