x(2x-5)=(2x+3)(x-8)

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Solution for x(2x-5)=(2x+3)(x-8) equation: 



x(2x-5)=(2x+3)(x-8)

We move all terms to the left:

x(2x-5)-((2x+3)(x-8))=0

We multiply parentheses

2x^2-5x-((2x+3)(x-8))=0

We multiply parentheses ..

2x^2-((+2x^2-16x+3x-24))-5x=0



We calculate terms in parentheses: -((+2x^2-16x+3x-24)), so:

(+2x^2-16x+3x-24)

We get rid of parentheses

2x^2-16x+3x-24

We add all the numbers together, and all the variables

2x^2-13x-24

Back to the equation:

-(2x^2-13x-24)



We add all the numbers together, and all the variables

2x^2-5x-(2x^2-13x-24)=0

We get rid of parentheses

2x^2-2x^2-5x+13x+24=0

We add all the numbers together, and all the variables

8x+24=0

We move all terms containing x to the left, all other terms to the right

8x=-24

x=-24/8

x=-3

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