x(2x-5)=(2x+1)(x-2)

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Solution for x(2x-5)=(2x+1)(x-2) equation: 



x(2x-5)=(2x+1)(x-2)

We move all terms to the left:

x(2x-5)-((2x+1)(x-2))=0

We multiply parentheses

2x^2-5x-((2x+1)(x-2))=0

We multiply parentheses ..

2x^2-((+2x^2-4x+x-2))-5x=0



We calculate terms in parentheses: -((+2x^2-4x+x-2)), so:

(+2x^2-4x+x-2)

We get rid of parentheses

2x^2-4x+x-2

We add all the numbers together, and all the variables

2x^2-3x-2

Back to the equation:

-(2x^2-3x-2)



We add all the numbers together, and all the variables

2x^2-5x-(2x^2-3x-2)=0

We get rid of parentheses

2x^2-2x^2-5x+3x+2=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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