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x(2x-4)=(2x+6)(x-2)
We move all terms to the left:
x(2x-4)-((2x+6)(x-2))=0
We multiply parentheses
2x^2-4x-((2x+6)(x-2))=0
We multiply parentheses ..
2x^2-((+2x^2-4x+6x-12))-4x=0
We calculate terms in parentheses: -((+2x^2-4x+6x-12)), so:We add all the numbers together, and all the variables
(+2x^2-4x+6x-12)
We get rid of parentheses
2x^2-4x+6x-12
We add all the numbers together, and all the variables
2x^2+2x-12
Back to the equation:
-(2x^2+2x-12)
2x^2-4x-(2x^2+2x-12)=0
We get rid of parentheses
2x^2-2x^2-4x-2x+12=0
We add all the numbers together, and all the variables
-6x+12=0
We move all terms containing x to the left, all other terms to the right
-6x=-12
x=-12/-6
x=+2
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