x(2x-3)=(2x+2)(x-5)

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Solution for x(2x-3)=(2x+2)(x-5) equation: 



x(2x-3)=(2x+2)(x-5)

We move all terms to the left:

x(2x-3)-((2x+2)(x-5))=0

We multiply parentheses

2x^2-3x-((2x+2)(x-5))=0

We multiply parentheses ..

2x^2-((+2x^2-10x+2x-10))-3x=0



We calculate terms in parentheses: -((+2x^2-10x+2x-10)), so:

(+2x^2-10x+2x-10)

We get rid of parentheses

2x^2-10x+2x-10

We add all the numbers together, and all the variables

2x^2-8x-10

Back to the equation:

-(2x^2-8x-10)



We add all the numbers together, and all the variables

2x^2-3x-(2x^2-8x-10)=0

We get rid of parentheses

2x^2-2x^2-3x+8x+10=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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