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x(2x+9)=3x-5=0
We move all terms to the left:
x(2x+9)-(3x-5)=0
We multiply parentheses
2x^2+9x-(3x-5)=0
We get rid of parentheses
2x^2+9x-3x+5=0
We add all the numbers together, and all the variables
2x^2+6x+5=0
a = 2; b = 6; c = +5;
Δ = b2-4ac
Δ = 62-4·2·5
Δ = -4
Delta is less than zero, so there is no solution for the equation
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