x(2x+3)=860

Solution for x(2x+3)=860 equation:

x(2x+3)=860

We move all terms to the left:

x(2x+3)-(860)=0

We multiply parentheses

2x^2+3x-860=0

a = 2; b = 3; c = -860;
Δ = b2-4ac
Δ = 32-4·2·(-860)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6889}=83$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-83}{2*2}=\frac{-86}{4}
=-21+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+83}{2*2}=\frac{80}{4}
=20
$