If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(2x+3)=324
We move all terms to the left:
x(2x+3)-(324)=0
We multiply parentheses
2x^2+3x-324=0
a = 2; b = 3; c = -324;
Δ = b2-4ac
Δ = 32-4·2·(-324)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-51}{2*2}=\frac{-54}{4} =-13+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+51}{2*2}=\frac{48}{4} =12 $
| 4x-9=3x-3 | | 3/8=n/6=n/18 | | 104.4=9(m+2.9) | | 3(-2x-4)=12 | | 7z=z+42 | | 2m*4=21 | | -11=x-19 | | -(7x+18)-2x=0 | | 4x=6x=(x+90)=(x+54) | | 0.25=d/12 | | 11+v=10 | | -2.4+2.1z=-8.7 | | H=3x+9 | | u=5+u8 | | 4p=116 | | 6(x+6)=-2x+28 | | 11z+7z/8=5/16 | | 8+0.06x=14.36 | | 13-5z=7 | | 7+3(x-5)=8-3(x-8) | | b−1.6÷4=−3b−1.6÷4=−3b=b= | | -4u-42=6(u+3) | | 4+6k=2 | | 3p+8=6+3p | | 7(p=3)=29.4 | | X+8+12x=124 | | 5(8-7x)=40 | | 1/16(x-10)=5+x | | y+6=20y= | | 3(5x+4)=12 | | 2(v-1)=5v+4 | | w-18=75 |