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x(2x+17)=174
We move all terms to the left:
x(2x+17)-(174)=0
We multiply parentheses
2x^2+17x-174=0
a = 2; b = 17; c = -174;
Δ = b2-4ac
Δ = 172-4·2·(-174)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-41}{2*2}=\frac{-58}{4} =-14+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+41}{2*2}=\frac{24}{4} =6 $
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