x(2x+12)=320

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Solution for x(2x+12)=320 equation:


Simplifying
x(2x + 12) = 320

Reorder the terms:
x(12 + 2x) = 320
(12 * x + 2x * x) = 320
(12x + 2x2) = 320

Solving
12x + 2x2 = 320

Solving for variable 'x'.

Reorder the terms:
-320 + 12x + 2x2 = 320 + -320

Combine like terms: 320 + -320 = 0
-320 + 12x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-160 + 6x + x2) = 0

Factor a trinomial.
2((-16 + -1x)(10 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-16 + -1x)' equal to zero and attempt to solve: Simplifying -16 + -1x = 0 Solving -16 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '16' to each side of the equation. -16 + 16 + -1x = 0 + 16 Combine like terms: -16 + 16 = 0 0 + -1x = 0 + 16 -1x = 0 + 16 Combine like terms: 0 + 16 = 16 -1x = 16 Divide each side by '-1'. x = -16 Simplifying x = -16

Subproblem 2

Set the factor '(10 + -1x)' equal to zero and attempt to solve: Simplifying 10 + -1x = 0 Solving 10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1x = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1x = 0 + -10 -1x = 0 + -10 Combine like terms: 0 + -10 = -10 -1x = -10 Divide each side by '-1'. x = 10 Simplifying x = 10

Solution

x = {-16, 10}

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