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x(2x+11)=156
We move all terms to the left:
x(2x+11)-(156)=0
We multiply parentheses
2x^2+11x-156=0
a = 2; b = 11; c = -156;
Δ = b2-4ac
Δ = 112-4·2·(-156)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-37}{2*2}=\frac{-48}{4} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+37}{2*2}=\frac{26}{4} =6+1/2 $
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