x(2)+204x-180=0

Solution for x(2)+204x-180=0 equation:

x(2)+204x-180=0

We add all the numbers together, and all the variables

x^2+204x-180=0

a = 1; b = 204; c = -180;
Δ = b2-4ac
Δ = 2042-4·1·(-180)
Δ = 42336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{42336}=\sqrt{7056*6}=\sqrt{7056}*\sqrt{6}=84\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(204)-84\sqrt{6}}{2*1}=\frac{-204-84\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(204)+84\sqrt{6}}{2*1}=\frac{-204+84\sqrt{6}}{2}
$