x(10-2.5x)=48

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Solution for x(10-2.5x)=48 equation: 



x(10-2.5x)=48

We move all terms to the left:

x(10-2.5x)-(48)=0

We add all the numbers together, and all the variables

x(-2.5x+10)-48=0

We multiply parentheses

-2x^2+10x-48=0

a = -2; b = 10; c = -48;
Δ = b2-4ac
Δ = 102-4·(-2)·(-48)
Δ = -284
Delta is less than zero, so there is no solution for the equation

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