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x(1-x)=5
We move all terms to the left:
x(1-x)-(5)=0
We add all the numbers together, and all the variables
x(-1x+1)-5=0
We multiply parentheses
-1x^2+x-5=0
a = -1; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-1)·(-5)
Δ = -19
Delta is less than zero, so there is no solution for the equation
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