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x(0.01x-0.02)=0
We multiply parentheses
0x^2-0.02x=0
We add all the numbers together, and all the variables
x^2-0.02x=0
a = 1; b = -0.02; c = 0;
Δ = b2-4ac
Δ = -0.022-4·1·0
Δ = 0.0004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.02)-\sqrt{0.0004}}{2*1}=\frac{0.02-\sqrt{0.0004}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.02)+\sqrt{0.0004}}{2*1}=\frac{0.02+\sqrt{0.0004}}{2} $
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