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x^2=450000
We move all terms to the left:
x^2-(450000)=0
a = 1; b = 0; c = -450000;
Δ = b2-4ac
Δ = 02-4·1·(-450000)
Δ = 1800000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1800000}=\sqrt{360000*5}=\sqrt{360000}*\sqrt{5}=600\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-600\sqrt{5}}{2*1}=\frac{0-600\sqrt{5}}{2} =-\frac{600\sqrt{5}}{2} =-300\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+600\sqrt{5}}{2*1}=\frac{0+600\sqrt{5}}{2} =\frac{600\sqrt{5}}{2} =300\sqrt{5} $
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