x^2-98x-224=0

Solution for x^2-98x-224=0 equation:

x^2-98x-224=0

a = 1; b = -98; c = -224;
Δ = b2-4ac
Δ = -982-4·1·(-224)
Δ = 10500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10500}=\sqrt{100*105}=\sqrt{100}*\sqrt{105}=10\sqrt{105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-10\sqrt{105}}{2*1}=\frac{98-10\sqrt{105}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+10\sqrt{105}}{2*1}=\frac{98+10\sqrt{105}}{2}
$