x^2-39x+368=0

Solution for x^2-39x+368=0 equation:

x^2-39x+368=0

a = 1; b = -39; c = +368;
Δ = b2-4ac
Δ = -392-4·1·368
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-7}{2*1}=\frac{32}{2}
=16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+7}{2*1}=\frac{46}{2}
=23
$