# x^2+9-486=0

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## Solution for x^2+9-486=0 equation:

x^2+9-486=0
We add all the numbers together, and all the variables
x^2-477=0
a = 1; b = 0; c = -477;Δ = b2-4acΔ = 02-4·1·(-477)Δ = 1908The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution:
$\sqrt{\Delta}=\sqrt{1908}=\sqrt{36*53}=\sqrt{36}*\sqrt{53}=6\sqrt{53}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{53}}{2*1}=\frac{0-6\sqrt{53}}{2} =-\frac{6\sqrt{53}}{2} =-3\sqrt{53}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{53}}{2*1}=\frac{0+6\sqrt{53}}{2} =\frac{6\sqrt{53}}{2} =3\sqrt{53}$

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