x^2+30x=3000

Solution for x^2+30x=3000 equation:

x^2+30x=3000

We move all terms to the left:

x^2+30x-(3000)=0

a = 1; b = 30; c = -3000;
Δ = b2-4ac
Δ = 302-4·1·(-3000)
Δ = 12900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12900}=\sqrt{100*129}=\sqrt{100}*\sqrt{129}=10\sqrt{129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10\sqrt{129}}{2*1}=\frac{-30-10\sqrt{129}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10\sqrt{129}}{2*1}=\frac{-30+10\sqrt{129}}{2}
$