w2+13w+24=0

Solution for w2+13w+24=0 equation:

w2+13w+24=0

We add all the numbers together, and all the variables

w^2+13w+24=0

a = 1; b = 13; c = +24;
Δ = b2-4ac
Δ = 132-4·1·24
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{73}}{2*1}=\frac{-13-\sqrt{73}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{73}}{2*1}=\frac{-13+\sqrt{73}}{2}
$