w-5/w+3=w-5/w+1+1

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Solution for w-5/w+3=w-5/w+1+1 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w-(5/w)+3 = w-(5/w)+1+1 // - w-(5/w)+1+1

w-w-(5/w)+5/w-1-1+3 = 0

w-w-5*w^-1+5/w-1-1+3 = 0

1 = 0

w belongs to the empty set

w belongs to the empty set

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